2 years ago

What is the domain of the function y=3 squared root of x -1 ? O-o -1 O 0 1

1 answer:

8 0

$y=3\sqrt{x-1}$

The domain is x ≥ 1 as x cannot be less than 1 or else it'll become negative in square root which you cannot find a value.

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What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)

UkoKoshka [18]

Answer:

$\boxed{m = - \frac{33}{14} }$

Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

Where

$m$ is a slope
$(x_1,~y_1)$ and $(x_2,~y_2)$ are the point of the line

So, the slope is

$(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1$

$(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}$

$m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }$

$m = \frac{\frac{11}{2} }{\frac{-7}{3} }$

$m = \frac{11}{2} \div (-\frac{7}{3} )$

$m = \frac{11}{2} \times (-\frac{3}{7} )$

$m = - \frac{33}{14}$

Happy to help:)

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Answer:

Step-by-step explanation:

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Answer:

Here you go! I have a graph for your answer!

Step-by-step explanation:

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