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3 years ago

8

A recipe for a smoothie calls for 0.75 pound of strawberries. If Kerry has 31.5 pounds of strawberries, how many batches of the

recipe can she make?

1 answer:

vodomira [7]3 years ago

5 0

42 batches. 31.5 divided by .75 = 42.

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Which equation is equivalent to<br> 5 - 2x = 4?

expeople1 [14]

-2x = -1
x = 1/2
Any equation that returns x=1/2 is a solution to this problem. For example, x= (3•4)/6 can be simplified so that x=1/2

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Divide.<br> Write your answer in simplest form.<br> -6/7 divided by (-5/4) =?

yulyashka [42]

Answer:

$\sf \dfrac{24}{35}$

Step-by-step explanation:

Use KCF method for fraction division.

Keep the first fraction.
Change the division operation to multiplication.
Flip the second fraction.

$\sf \dfrac{-6}{7} \div \dfrac{-5}{4}=\dfrac{-6}{7}*\dfrac{-4}{5}$

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1 year ago

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2 years ago

What is 6 divied 192 please show work

suter [353]

The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.

So we will approach this is in two ways.

If this was meant to be "divided by" then it would look like this:
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If this was meant to be "divided to" then it would look like this:
192 / 6

Let us first solve for the first possible problem:
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0.0312 would be the answer.

Let us then solve for the second possible problem:
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Answer:

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Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

$\sf \cos(\theta)=\dfrac{A}{H}$

where:

$\theta$ is the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Given:

$\theta$ = ∠KLM
A = LN = 8
H = KL = 15.2

$\implies \sf \cos(KLM)=\dfrac{8}{15.2}$

$\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)$

$\implies \sf \angle KLM=58.24313614^{\circ}$

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}$

Given:

r = 15.2
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