The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
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Answer:
C
Step-by-step explanation:
First of all, lets get y on its own side of the equation.

This is slope intercept form, y=mx+b, where m is slope.
we can see that m=2, so the slope is 2 or 
Answer:
15
Step-by-step explanation:
As you can see on the side it says 15 and that is the length of the structure and it would be the same all around