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3 years ago

Which statement is true?

Mathematics

1 answer:

Zepler [3.9K]3 years ago

4 0

Answer: A

Step-by-step explanation:

Square root of 35 is 5.9161

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I need this answer ASAP

AnnZ [28]

Answer:

trapezoid one is 336 inches squared

trapezoid two is 9 inches squared

Step-by-step explanation:

The formula for a trapezoid is b1+b2 so the number on the top line = the number on the bottom line, you then multiply your new number by the height which is the number bye the dotted red line.

Hope this helps!

3 0

3 years ago

Solve: + 12x = 9<br> Ox=3/5 :: 6<br> O x= 6 745<br> O=-6+ 745<br> O *=-6_315

Alex_Xolod [135]

Answer:

$x = \frac{3}{4}$

Step-by-step explanation:

$12x = 9$

Divide both sides by 12:

$\frac{12x}{12} = \frac{9}{12}$

Simplify the fraction:

$x = \frac{9}{12}$

Find the greatest common factor of the numerator and denominator:

$x = \frac{3.3}{4.3}$

Factor out and cancel the greatest common factor:

$x = \frac{3}{4}$

5 0

3 years ago

The graph of r = -3 + 5cos theta is symmetric about the __________.

Drupady [299]

I believe it it will be the across the y axis

8 0

3 years ago

Read 2 more answers

Tood knows that the ratio of boys and girls in his class is 3:5. Since 12 of the students are boys, he says there must be 36 stu

Vesna [10]

Answer:

=99

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do i graph y=1/2Sinø/2?

podryga [215]

$\fb \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------$

$\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}$

$\bf \bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

now, with that template in mind,

$\bf \stackrel{parent~function}{y=sin(\theta )}\qquad \qquad y=\stackrel{A}{\frac{1}{2}}sin\left(\stackrel{B}{\frac{1}{2}}\theta \right)
\\\\\\
Amplitude\implies \frac{1}{2}
\\\\\\
Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{1}{2}}\implies 4\pi$

which is pretty much the same sin(θ) function, but squished by 1/2 and elongated up to 4π, check the picture below.

7 0

3 years ago