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3 years ago

Find the length of side x in simplest radical form with a rational denominator.

Mathematics

1 answer:

madreJ [45]3 years ago

8 0

Answer:

x=2√5

Step-by-step explanation:

1st method:

sin(30)=opposite/hypotenuse=√5/x

sin(30)x=√5

x=√5/sin(30)

x=2√5

2nd method:

cos(60)=adjacent/hypotenuse=√5/x

cos(60)x=√5

x=√5/cos(60)

x=2√5

3rd method:

This is a 30-60-90 triangle, so we can multiply the short side, √5, by 2, to get x=2√5

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Can anyone help me with my geometry?

8090 [49]

8.4 $\pi$ cm

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3 years ago

A. Why does the provided equation support the fact that there is a horizontal asymptote of F(x) that is not

aniked [119]

Applying limits, it is found that since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

The function is given by:

$F(x) = \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

The horizontal asymptote is the limit of the function as x goes to infinity, hence:

$y = \lim_{x \rigtharrow \infty} F(x) = \lim_{x \rigtharrow \infty} \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

Considering only the terms with the highest exponents:

$y = \lim_{x \rigtharrow \infty} \frac{ax^2}{2x^2} = \frac{a}{2}$

Since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

For more on horizontal asymptotes and limits, you can check brainly.com/question/11598999

3 0

2 years ago

Could someone please help me

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

I think its c but I could be wrong

7 0

3 years ago

What is the slope of the line that passes through the points (-2, -5)(−2,−5) and (-3, -6) ?(−3,−6)? Write your answer in simples

pogonyaev

Answer:

0 & 0

Step-by-step explanation:

In order to find the answer to these two questions you need to use the slope formula, substitute, subtract, and simplify if needed.

$(-2,-5),(-2,-5) = (x^1,y^1),(x^2,y^2)$

Slope formula = $m=\frac{y^2-y^1}{x^2-x^1}$

Substitute: $\frac{-5--5}{-2--2} =$

$\frac{-5--5}{-2--2} =-5--5 = 0$

$-2--2 = -2+2=0$

$= 0$

$(-3,-6),(-3,-6)=(x^1,y^1),(x^2,y^2)$

$m=\frac{-6--6}{3--3}$

$-6+6=0$

$-3+3=0$

$=0$

Hope this helps.

7 0

2 years ago

Jordan swam 4 laps. Each lap is 100 meters. Jordan’s average speed for the first 3/4 of his swim was 40 meters per minute, and f

Leya [2.2K]

Answer/step-by-step explanation:

The 300/40 comes from the fact that ¾ of a 400 meter swim is 300 meters, and if you want to know how long he took to do that, you need to divide by the speed, 40 meters per minute (meters divided by meters per minute = minutes). Likewise with the 100/35—that’s the last 100 meters he swam, at the slightly slower speed.

Just to bring it all the way home, average speed is total distance divided by total time. that the total distance is 400 meters. You know the total time is 300/40 + 100/35. Average speed, then, is:

Average Speed: $= \frac{400}{\frac{300}{40} +\frac{100}{35} }$

Round: 39 meters per minute

I think if wrong I'm sorry

5 0

3 years ago