Question

If the poh of vinegar is 9.45, what is its [oh− ]? round to the nearest hundredth. × 10n m n =

Answer 1

The [OH] of vinegar to the  nearest hundredth is 2.82 * 10^-5

How to calculate the [OH] of a substance:

The sum of the pH and pOH of a substance is 14. Mathematically

[OH−] = Antilog (pOH)

Given the following parameters

[OH−] = Antilog (9.45)

Substitute

[OH−] = 2.82 * 10^-5

Hence the [OH] of vinegar to the  nearest hundredth is 2.82 * 10^-5

Learn more on pH and pOH here:brainly.com/question/13557815