The [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5
The sum of the pH and pOH of a substance is 14. Mathematically
[OH−] = Antilog (pOH)
Given the following parameters
[OH−] = Antilog (9.45)
Substitute
[OH−] = 2.82 * 10^-5
Hence the [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5
Learn more on pH and pOH here:brainly.com/question/13557815
Answer:
Step-by-step explanation:
No
V =48 cm^3
The volume of a prism is given by
V = l*w*h
V = 3*4*4
I assume that it is 1, 3, 4, and 5. Correct me if I'm wrong. Plz give brainliest if I'm right.
