If the poh of vinegar is 9.45, what is its [oh− ]? round to the nearest hundredth. × 10n m n =

1 answer:

7 0

The [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5

<h3>How to calculate the [OH] of a substance:</h3>

The sum of the pH and pOH of a substance is 14. Mathematically

[OH−] = Antilog (pOH)

Given the following parameters

[OH−] = Antilog (9.45)

Substitute

[OH−] = 2.82 * 10^-5

Hence the [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5

Learn more on pH and pOH here:brainly.com/question/13557815

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Anuta_ua [19.1K]

Answer:

$278,800,000$ (Real Number) or $2.788 *10^8$ (Scientific Notation)

Concepts:

Parenthesis: ( )

Exponents: x²

Multiplication: ×

Division: ÷

Addition: +

Subtraction: -

Step-by-Step Solution:

$8.2*10^2*3.4*10^5$

Simplify exponents and square roots

$8.2*10^2*3.4*10^5$

$8.2*10^2*3.4*100000$

$8.2*100*3.4*100000$

$820*3.4*100000$

$2788*100000$

$278800000$

<h2>Answer:</h2>

278,800,000

Why learn this:

Order of operations is a basic rule of algebra. It tells us what to solve first when we have an equation with multiple functions, which is something that you will likely encounter throughout your math studies. The order is: Parentheses, Exponents, Multiplication and Division, then finally Addition and Subtraction. Remember that when you're solving within the parentheses, the Order of Operations applies!

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