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Damm [24]
3 years ago
6

Nitrogen fixation is carried out mainly by...

Biology
1 answer:
Ghella [55]3 years ago
8 0
I think the answers are 2
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16. Why should the recessive phenotype be used first to determine the q squared value instead of the dominant phenotype to deter
podryga [215]

The recessive phenotype is used first to determine the q squared value because it is only expressed when h0m0zygous.

<h3>What is a recessive phenotype?</h3>

A recessive phenotype is a phenotype which expresses the recessive trait of a gene.

The recessive phenotype is always h0m0zygous for that triat to be expressed.

In the Hardy-Weinberg equilibrium equation, the allele and phenotype frequencies are given as follows:

  • p^2 + 2pq + q^2 = 1

where;

  • p^2 is the h0m0zygous dominant phenotype frequency
  • 2pq is the heterozygous phenotype frequency
  • q^2 is the h0m0zygous recessive phenotype frequency

Therefore, the recessive phenotype is used first to determine the q squared value because it is only expressed when h0m0zygous.

Learn more about recessive phenotype at: brainly.com/question/22117

8 0
2 years ago
Punnett squares are used to show possible combinations of alleles or to predict the probability of a trait occurring in offsprin
Andrei [34K]

Answer:

The correct answer would be 2 in 4.

According to the question Xo and XO show codominance and express themselves completely when present in heterozygous condition. Cats bearing XoXO show patchwork of black and orange fur and are called tortoiseshell cats.

Xo codes for orange color fur and XO codes for black color fur. In addition, Y chromosome does not contain any gene associated with fur color.

Now, genotype of mother cat is XOXO (orange fur). So, the gametes formed would be XO only.

The genotype of father cat is XoY(black fur). So, the gametes would be Xo and Y.

The cross would lead to the formation of two male cats each having XOY as their genotype and two female cats each with XOXo as their genotype.

Hence, both the male cats would show orange fur and both the female cats would show patchwork of orange and black fur.

Therefore, we can conclude that 2 out of 4 would exhibit tortoiseshell coloring.

3 0
3 years ago
Read 2 more answers
Thinking creatively about evolutionary mechanisms, identify at least two schemes that could generate allelic polymorphism in a p
Ede4ka [16]

Complete question:

Thinking creatively about evolutionary mechanisms, identify at least

two schemes that could generate allelic polymorphism in a population except natural selection that favors heterozygotes.

<u>Select the two correct answers.</u>

-inbreeding among individuals in the population

-purifying selection against mutational variants of alleles in the population

-continuous migration of individuals with new alleles into the population

-mutations that do not severely affect viability and reproductivity

-genetic drift of alleles common in the population

-events leading to genetic bottleneck effect

Answer:

The two events that might favor heterozygotes among the options are  

  • The Continuous migration of individuals with new alleles into the population
  • Mutations that do not severely affect viability and reproductivity.  These might favor heterozygous frequencies.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files.

Download pdf
3 0
3 years ago
Nuclear power plant waste water has been blamed for _____.
Rzqust [24]
Aesthetic potentially due to the decay but also environmental
7 0
3 years ago
Which part of the compound light microscope is used to change magnification?
coldgirl [10]

Answer: Part C

That’s correct because it contains the lenses magnification.

8 0
3 years ago
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