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tekilochka [14]
3 years ago
11

Plsssssss help i need it.

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
I would say decreasing!
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The length of a rectangle is five times its width.
kykrilka [37]

Answer:

w=10

L=50

Step-by-step explanation:

<h2><em>Length=5w</em></h2><h2><em>Width=W</em></h2>

6w=60

----   ----

6       6

w=10

5(10)=50

L=50

Also can you make me the top answer?

4 0
3 years ago
What is the missing reason in step 6? SSS congruency theorem CPCTC definition of a parallelogram opposite sides in a parallelogr
NARA [144]

For the two parallelogram to be congruent, their corresponding sides must be equal

<h3>Congruent figures</h3>

Two figures are said to be congruent if they are of the same shape and their corresponding sides and angles are congruent to each other. The SSS congruency theorem states that two figures are congruent of all their sides are congruent.

For the two parallelogram to be congruent, their corresponding sides must be equal

Find out more on similar figures at: brainly.com/question/26173060

7 0
2 years ago
Write the sum of the numbers as the product of their gcf and another sum 32 and 20
pav-90 [236]
Ymm makes no sense but its pulsing so yea the answer is 52
7 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
I need help finding a measure
Sedbober [7]

Answer:

Which measure?

Step-by-step explanation:

8 0
3 years ago
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