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Marysya12 [62]
3 years ago
15

— 3y — 4х = -11 3y — 5х = — 61

Mathematics
2 answers:
storchak [24]3 years ago
6 0
Idkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
shtirl [24]3 years ago
6 0

Answer:

x = 8

y = -7

Step-by-step explanation:

-3y - 4х = - 11  .................................... (1)

3y - 5х = - 61 ..................................... (2)

From equation (2),

3y = -61 + 5x

divide through by 3 to have 'y' as the subject

y = -61/3 + 5x/3 ........................ (3)

Substitute for 'y' in equation (1) to get 'x'

Putting equation (3) in equation (1)

-3 (-61/3 + 5x/3) - 4x = -11

Open the bracket first

61 + (-5x) - 4x = -11

61 - 5x - 4x = -11

61 - 9x = -11

collect like terms

61 + 11 = 9x

72 = 9x

divide through by 9

8 = x

∴ x = 8

Substitute for x in either of the above equation to get 'y'

Using equation (3)

y = -61/3 + 5(8)/3

simplify

y = -61/3 + 40/3

common denominator

y = (-61 +40) / 3

y = -21 / 3

y = -7

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She can make 60 bracelets

Hope this helped! :)

5 0
3 years ago
Help................​
Rina8888 [55]

Answer:  DB is 5

Step-by-step explanation:

Alright, lets get started.

Since given that AD is parallel to CB.

And AB is parallel to CD.

And the angle A is given as 90°

It means the given figure is a rectangle.

And the diagonals of the rectangle are equal to each other.

So, DB=AC

So, DB=5

Hence the answer is 5 ...     Answer

Hope it will help :)

4 0
2 years ago
What is the center and radius of the equation (x-8)^2 +(y+6)^2=13
tatyana61 [14]

Answer:

see explanation

Step-by-step explanation:

the equation of a circle in standard form is

(x - a)² + (y - b)² = r²

where (a, b) are the coordinates of the centre and r is the radius

(x - 8)² + (y + 6)² = 13 is in this form

with centre = (8, - 6) and r = \sqrt{13}



6 0
2 years ago
5/9 × 8/11 what is the answer
nikitadnepr [17]

Answer:

\frac{5}{9}  \times  \frac{8}{11}  =  \frac{5 \times 8}{9 \times 11}  =  \frac{40}{99}  = 0.4040

7 0
3 years ago
Read 2 more answers
Line Equation from Two Points
Verdich [7]

Hi!

We can use <u>point-slope form </u>to solve this.

y-y_{1} =m(x -x_{1})

y_{1}<em> and </em>x_{1}<em> will be from one of the points.</em>

<u>First, we have to find </u>m<u>, the slope. We can use the slope equation to get this.</u>

\frac{y_{1} -y_{2} }{x_{1} -x_{2} }

<em>Plug in your points:</em>

\frac{4-0}{8-(-8)} =\frac{4-0}{8+8} =\frac{4}{16} =\frac{1}{4}

Your slope is \frac{1}{4}

<u><em>Now plug points and slope into point-slope equation. We will use (8, 4).</em></u>

y-4=\frac{1}{4} (x-8)

Now, if you want to get it into y = mx + b form, you have to solve for y:

y-4=\frac{1}{4} (x-8)

y-4=\frac{1}{4} x-2

y=\frac{1}{4} +2

Your equation is y=\frac{1}{4} +2

<u><em>For more information on how to get the equation of a line when given two points, see here:</em></u>

brainly.com/question/986503

7 0
2 years ago
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