Answer:
The answer is "
"
Step-by-step explanation:
Given value:
![\to \bold{ \sqrt[3]{x^5y} }](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7B%20%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%7D)
![\to \sqrt[3]{x^5y} =(x^5y)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cto%20%5Csqrt%5B3%5D%7Bx%5E5y%7D%20%3D%28x%5E5y%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
formula:
The final value is: 
Since dimes + quarters = 22
And dimes are 0.10 cents as quarters = 0.25 cents
Let’s make d = dime, q = quarter
d + q = 22
0.10d + 0.25q = 4.00
Let’s use substitution
d + q = 22, get d or q by itself
d = 22 - q (plug into second equation)
0.10(22-q) + 0.25q = 4
2.2 - 0.10q + 0.25q = 4
2.2 + 0.15q = 4
0.15q = 1.8, q = 12
Since there are 12 quarters you know there are 10 dimes (22 in total)
Solution: 10 dimes, 12 quarters
a) 247 ÷ 11 = 22 r.5 <em>since there is a remainder it is not a factor</em>
b) 247 ÷ 13 = 19 there is no remainder so this is a factor! The other factor is 19.
Answer: B, D
Answer:
m = cd³
Step-by-step explanation:
mass of is proportional to the diam
sphere cubed
Symbolically, this can be written as:
m = cd³
Answer:
The answer is D i guess . ( Not completely sure )
