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Daniel [21]
4 years ago
14

sample daat reflects shipments received from 3 different vendors Vendor Defective Acceptable 1 16 133 2 25 74 3 24 187 what is c

orrect hypothesis to determine if quality is associated with vendor calculate the value of the test statistic specifiy decision rule at the 1% significance level What is your conclusion
Mathematics
1 answer:
Sergeu [11.5K]4 years ago
5 0
Question: W<span>hat is the correct hypothesis to determine if quality is associated with vendor?

By looking at other resources, I have found the choices given for this question. They are the following:

a. Null</span>: Quality and source of shipment (vendor) are independent; Alternative: Quality and source of shipment (vendor) are dependent.
b. Null: Quality and source of shipment (vendor) are dependent; Alternative: Quality and source of shipment (vendor) are independent.

The test that would be applicable for this type of data would be the Chi-Square Test for Independence. As the name implies, the null hypothesis should be that the two factors are independent since that will be what we will be testing for.

ANSWER: a. Null: Quality and source of shipment (vendor) are independent; Alternative: Quality and source of shipment (vendor) are dependent.

Question: Calculate the value of the test statistic.

Please refer to the attached document for the complete computation for this part. Generally, we need to find the expected value for each cell in the table and perform some calculation explained in the document.

ANSWER: The test statistic is 12.80.

Question: S<span>pecify decision rule at the 1% significance level.

We can get the critical value for Chi-square tests by first looking for the degree of freedom. We can get the df by evaluating the following expression: (rows-1)*(columns-1). In our case, the number of columns is 2 and the number of rows is 3. The df is therefore (2-1)(3-1)=(1)(2)=2.

We then look at a table to determine what the value at the 1% significance level and df of 2 is.

ANSWER: We reject the null hypothesis if the test statistic is greater than the critical value which is 9.2103.

Question: What is your conclusion?
</span>
Since the test statistic (12.80) is greater than the critical value (9.2103), we can therefore tell that it is in the area for rejection.

Thus, we reject the null hypothesis.

ANSWER:
There is enough evidence to conclude that the quality and source of shipment (vendor) are NOT independent.
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Perform the specified operations on the polynomials: Subtract 2x2−3xy+4y2from 3x2−5xy−6y2
tankabanditka [31]

Answer:

Solution to the given expression is (x^2 -10y^2 -2xy)

Step-by-step explanation:

Here, the given expression are:

P(x) = 2x^2- 3xy+4y^2\\Q(x) = 3x^2 - 5xy-6y^2

To Solve for : Q(x)  - P(x)

Now substitute the value of P(x) and Q(x) , we get:

Q(x) - P(x) = P(x) = (3x^2 - 5xy-6y^2) - (2x^2- 3xy+4y^2)\\= 3x^2 - 5xy-6y^2 - 2x^2+3xy-4y^2\\=x^2-10y^2-2xy\\\implies Q(x) - P(x) = (x^2-10y^2-2xy)

Hence solution to the given expression is (x^2 -10y^2 -2xy)

8 0
4 years ago
2. Which statement below is the hypothesis
yarga [219]

The hypothesis of the statement is I can join an orchestra.

The hypothesis refers to a presumption or statement which may hold true or not pending the outcome of an experiment or study.

Here, the hypothesis will be that, the subject can join an orchestra.

However, before validating this hypothesis, we need to establish that the subject can play the clarinet, which is the test which would be carried out.

Learn more : brainly.com/question/23056080?referrer=searchResults

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3 years ago
Without graphing, classify the following system as independent, dependent, or inconsistent. y=-3x+4 and 6x+2y=8
forsale [732]

Answer:

Dependent

Step-by-step explanation:

y=-3x+4 and 6x+2y=8

Lets solve the second equation for y and then substitute it in first equation

6x+2y=8

Subtract 6x on both sides

2y=-6x+8

Divide by 2 on both sides

y=-3x+4

Now we plug it in first equation for y

-3x+4=-3x+4

Add 3x on both sides

4=4

Both sides are same, they are equal. the system has infinite solutions.

They are said to be dependent

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3 years ago
⚠⚠I SEE YOU DONT YOU DARE IGNORE THIS⚠⚠⚠⚠
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Answer:

2=(3,-2)

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3 0
3 years ago
Read 2 more answers
In a school of 450 people 110 are in the choir 240 are in a band and 60 are in both
zhannawk [14.2K]

<em>The question doesn't require any specific probabilities, but I'm adding my own calculations to make it easier for you to solve your own problem</em>

Answer:

<em>Questions added and answered below</em>

Step-by-step explanation:

<u>Venn Diagram </u>

When we have different sets, some of them belong only to one set, some belong to more than one, some don't belong to any of them. This situation can be graphically represented by the Venn Diagrams.

Let's analyze the data presented in the problem and fill up the numbers into our Venn Diagram. First, we must use the most relevant data: there are 60 people in both the choir and the band. This number must be in the common space between both sets in the diagram (center zone, purple).

We know there are 110 people in the choir, 60 of which were already placed in the intersection zone, so we must place 110-60=50 people into the blue zone, belonging to C but not to B.

We are also told that 240 people are in a band, 60 of which were already placed in the intersection zone, so we must place 240-60=180 people into the red zone, belonging to B but not to C.

Finally, we add the elements in all three zones to get all the people who are in the choir or in the band, and we get 50+60+180=290. Since we have 450 people in the school, there are 450-290=160 people who are not in the choir nor in the band.

The question doesn't ask for a particular probability, so I'm filling up that gap with some interesting probability calculations like

a) What is the probability of selecting at random one person who is in the band but not in the choir?

The answer is calculated as

\displaystyle P(A)=\frac{180}{450}=0.4

b) What is the probability of randomly selecting one person who belongs only to one group?

We look for people who are in only one of the sets, they are 50+180=230 people, so the probability is

\displaystyle P(B)=\frac{230}{450}=0.51

b) What is the probability of selecting at random one person who doesn't belong to the choir?

We must add the number of people outside of the set C, that is 180+160=340

\displaystyle P(C)=\frac{340}{450}=0.76

7 0
3 years ago
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