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2 years ago

(3-i)/(3+i) ayudenme por fa

Mathematics

1 answer:

RUDIKE [14]2 years ago

8 0

Answer:

6-1+1

this is the ans to ur question

thanks

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Sales rise from £400 a week to £504 a week. Calculate the percentage increase

Andrew [12]

Answer:

26%

Step-by-step explanation:

percent change = (new number - old number)/(old number) * 100%

Here, the new number is £504, and the old number is £400.

percent change = (£504 - £400)/(£400) * 100% =

= £104/£400 * 100% = 0.26 * 100% = 26%

5 0

3 years ago

Simplify negative 9 over 6 divided by 3 over negative 2. . (5 points) a 3 b 1 c −1 d −3

vladimir2022 [97]

Answer:

b) 1

Step-by-step explanation:

$\frac{9}{6} \times \frac{2}{3} = \frac{18}{18}$

$\frac{18}{18} = 1$

6 0

3 years ago

Mrs. DeMarco wants to estimate the height of her garage

valkas [14]

Answer:

length of baseball bat.

Step-by-step explanation:

she can measure the bat and times by how many times she could fit the bat there u know

6 0

3 years ago

Luke bought 256256256 ounces of strawberries. He divided them evenly between 888 different pies. How many pounds of strawberries

SIZIF [17.4K]

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

$\text{256 ounces}=\frac{256}{16}\text{ pounds}=16\text{ pounds}$

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

$\text{Pounds of strawberries on each pie}=\frac{16}{8}$

$\text{Pounds of strawberries on each pie}=2$

Therefore, Luke put 2 pounds strawberries on each pie.

4 0

3 years ago

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

3 years ago