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strojnjashka [21]
3 years ago
7

Find the equation of the line in slope-intercept form that passes through (2, 7) and (-1, 5).

Mathematics
1 answer:
Elena L [17]3 years ago
6 0
The answer is given above

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Write 15,625 in exponents
Brilliant_brown [7]

Answer:

we have to do it in exponential form?

Step-by-step explanation:

Answer:The exponent form of 15625 is 1.5625 × 104.

4 0
3 years ago
A racing bicycle with a cash price of 900 at at 90 down down and 40.50 per month for 24 months ​
Sav [38]

Answer:

1062 for 24 monthly payments plus 90$ down payment

Step-by-step explanation:

90+40.50x               x=24 months

40.5 x 24 = 972

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3 0
3 years ago
Six less than twice a number , x, is 39. what is the value of x
katovenus [111]

Answer:

x=45/2

Step-by-step explanation:

2x-6=39

2x=39+6

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7 0
3 years ago
Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

    \frac{5}{3} = \frac{-2}{3} (0) + c

    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

7 0
3 years ago
30=3(v–8) what is the value for v
Vilka [71]
V= 18

hope this helped!!!
8 0
3 years ago
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