Answer:

Step-by-step explanation:


Therefore ,

I believe the answer should be -4+x= -4x.
I hope this helps :)
Answer:
Center (-5,4) radius 3
Step-by-step explanation:
The standard equation of a circle is
(x-h)^2+(y-k)^2=r^2
where the center is (h,k) and r is the radius
so h=-5 in this case and k is 4
r^2=9 so r=3
×<_ 24 is the answer I believe.
Answer:
The third one
Step-by-step explanation: