Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
25 + 6 - 15 + 25 - 10 + 14 - 21
31 - 15 + 25 - 10 + 14 - 21
16 + 25 - 10 + 14 - 21
41 - 10 + 14 - 21
31 + 14 - 21
45 - 21
24
Answer:
x intercept [a]=3
y intercept [b]=-5
we have
equation of a line is:
x/a+y/b=1
x/3+y/-5=1
(5x-3y)=15
5x-3y-15=0 is a required equation
Answer:
w=2 w = -9
Step-by-step explanation:
w^2 + 7w - 18 = 0
We can factor this equation
What 2 numbers multiply to -18 and add to 7
9*-2 = -18
9+-2 = 7
(w-2) (w+9) = 0
Using the zero product property
w-2 = 0 w+9 =0
w=2 w = -9
