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UkoKoshka [18]
3 years ago
8

Evelyn earned a score of 86 on Exam A that had a mean of 71 and a standard deviation of 20. She is about to take Exam B that has

a mean of 550 and a standard deviation of 40. How well must Evelyn score on Exam B in order to do equivalently well as she did on Exam A? Assume that scores on each exam are normally distributed.
Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

580

Step-by-step explanation:

Assuming that the answer should be in terms of z scores, we can calculate the z score as

z = (observed value - mean)/(standard deviation)

For the first exam, the observed value is 86, the mean is 71, and the standard deviation is 20. The z score fot that exam is

z = (86-71)/20 = 0.75

Then, for the second exam, Evelyn has to do equivalently well, so the z score must be the same. Therefore, we have

0.75 = (observed score - 550)/40

multiply both sides by 40 to remove a denominator

0.75 * 40 = observed score - 550

add 550 to both sides to isolate the observed score

0.75 * 40 + 550 = observed score = 580

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Answer

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Step-by-step explanation:

Let's use "x" to represent burger meals and "y" to represent hot dog meals.

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We have to first compare both families' and then eliminate one of our common variables, either the "x" or "y".

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=

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We now know the value of "y" <em>or </em>one hot dog meal. Next, we want to solve for "x", our variable for the hamburger meal... We will plug in our y value to help us...

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and...

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