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amid [387]
3 years ago
5

a crane lifts a pallet of concrete blocks 9 ft from the back of the truck. the truck drives away and the crane lowers the pallet

15 ft. what is the final position of the pallet relative to where it started in the back of the truck?
Mathematics
1 answer:
goblinko [34]3 years ago
8 0
Answer:
The final position is 5 feet below the back of the truck
Step-by-step explanation:
* Lets explain how to solve the problem
- A crane lifts a pallet of concrete blocks 8 feet from the back of
a truck
- The crane lowers the pallet 13 feet after the truck drives away
- Assume that the zero level of the position of the ballet of concrete
blocks is the back of the truck
∵ The crane lifts the pallet of concrete blocks 8 feet from the back
of the truck
- That means it take the pallet from zero to 8
∴ The height of the pallet of concrete blocks is 8 feet over
the starting position
∵ The crane lowers the pallet of concrete blocks 13 feet
- That means the crane lower the pallet from the height 8 and
lift it down 13 feet, so we must to take out from the 8 feet the
13 feet to find the final position of the pallet of concrete blocks
∴ The pallet position is ⇒ 8 - 13 = -5
∴ The position of the pallet of concrete blocks is 5 feet below the
starting position which is the back of the truck
* The final position is 5 feet below the back of the truck
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10/100=0.1
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5.3624785e+55

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A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
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Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

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t = Time in years.

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Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

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7 0
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Do you know the answer toPart A: 25% of 50 = Part B: 25% of 60 = Part C: 50% of 60 = Part D: 75% of 60 = Part E: 75% of 30 = Par
Verdich [7]

Answer:

Part A: 25% of 50 = 12.5

Part B: 25% of 60 = 15

Part C: 50% of 60 = 30

Part D: 75% of 60 = 45

Part E: 75% of 30 = 22.5

Part F: 100% of 22.5 = 22.5

Part G: 10% of 22.5 = 2.25

Part H: 50% of 45.7 = 22.85

Step-by-step explanation:

To find - Do you know the answer to

              Part A: 25% of 50 =

              Part B: 25% of 60 =

              Part C: 50% of 60 =

              Part D: 75% of 60 =

              Part E: 75% of 30 =

              Part F: 100% of 22.5 =

              Part G: 10% of 22.5 =

              Part H: 50% of 45.7 =

Proof -

Part A :

25% of 50 =  \frac{25}{100} *50 = \frac{1}{4}*50 = 12.5

⇒25% of 50 = 12.5

Part B :

25% of 60 =  \frac{25}{100} *60 = \frac{1}{4}*60 = 15

⇒25% of 60 = 15

Part C :

50% of 60 =  \frac{50}{100} *60 = \frac{1}{2}*60 = 30

⇒50% of 60 = 30

Part D :

75% of 60 = \frac{75}{100} *60 = \frac{75}{10}*6 = 45

⇒75% of 60 = 45

Part E :

75% of 30 = \frac{75}{100} *30 = \frac{75}{10}*3 = 22.5

⇒75% of 30 = 22.5

Part F :

100% of 22.5 = \frac{100}{100} *22.5 = 22.5

⇒ 100% of 22.5 = 22.5

Part G :

10% of 22.5 = \frac{10}{100} *22.5 = 2.25

⇒ 10% of 22.5 = 2.25

Part H :

50% of 45.7 =  \frac{50}{100} *45.7 = \frac{1}{2}*45.7 = 22.85

⇒50% of 45.7 = 22.85

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