Answer:
<h3>Density = 0.5 g/cm³</h3>
Explanation:
Density of a substance can be found by using the formula
From the question
mass = 32g
To find the density we must first find the volume of the block
From the question the block is a cuboid
Volume of cuboid = length × width × height
length = 8 cm
width = 4 cm
height = 2 cm
Volume of block = 8 × 4 × 2 = 64 cm³
Substitute the values into the above formula and solve for the density
That's....
We have the final answer as
Density = 0.5 g/cm³
The block will float because it's density is less than the density of water which is
1 g/cm³
Hope this helps you
Each column is called a group<span>. The elements in each </span>group have<span> the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons.</span>
Answer:
how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?
(A) n=m/M,
n(Al)=5.4/27=0.2 moles
n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles
Number of oxygen atoms= n(O2)*Avogadro's number
=0.15*6.02*10^23=9.03*10^22 oxgyen atoms
(B)
n=m/M
n(Al)=0.6/27=0.02222 moles
n(O2)=n(Al)*3/4=0.016666 moles
m=n*M
m(O2)=0.0166666*32=0.53333 grams
Answer:
i think O.C is correct answer
Explanation:
<h2>hope it's helps you </h2>
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24 ounces of 8% solution and 8 ounces of 16% solution to create 32 ounces of 10% solution.
OK. We need 32 ounces of 10% solution and we have 16% and 8% solutions available. So let's set up an equation to solve. I'll use the variable X to represent the amount of 8% solution needed.
X*0.08 + (32-X)*0.16 = 32*0.10
Now simplify and solve.
X*0.08 + (32-X)*0.16 = 32*0.10
X*0.08 + 32*0.16 - X*0.16 = 32*0.10
X*0.08 - X*0.16 = 32*0.10 - 32*0.16
X(0.08 - 0.16) = 32(0.10 - 0.16)
X(-0.08) = 32(-0.06)
X = 32(-0.06)/(-0.08)
X = 24
So we need 24 ounces of 8% solution and (32 - 24) = 8 ounces of 16% solution.
