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Tju [1.3M]
3 years ago
7

Which of the following sets of ordered pairs is a function?

Mathematics
1 answer:
mina [271]3 years ago
4 0

Answer:

A

Step-by-step explanation:

for every input there's one output

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Line p has a slope of -3. Line t is perpendicular to line p and passes through the point (9,2). What is the equation for line t?
olganol [36]

Answer:

y = (1/3)x - 1

Step-by-step explanation:

The product of the slopes of perpendicular lines is -1. That makes the slopes of perpendicular lines negative reciprocals. Since line p has slope -3, the slope of line t is 1/3. Also, line t passes through point (9, 2).

y = mx + b

m = slope

y = (1/3)x + b

Now we replace x and y with the x- and y-coordinates of the given point, respectively, and we solve for b.

2 = (1/3)(9) + b

2 = 3 + b

b = -1

Now we replace b with -1.

y = (1/3)x - 1

8 0
3 years ago
A jar contains 12 blue pens, 7 black pens, and 3 red pens. Marco picks two red pens at random, without replacement.
natta225 [31]
A) 3/22x2/22 represents the probability
5 0
4 years ago
What’s the answer to this important problem it is very idk
White raven [17]
1) 4/(1/5)

=4 ÷ 1/5
to divide fractions, multiply by the reciprocal/inverse of 1/5

=4 * 5/1
=20


4) (7/9)/7

=7/9 ÷ 7
to divide fractions, multiply by the reciprocal/inverse of 7

=7/9 * 1/7
multiply numerators; multiply denominators

=(7*1)/(9*7)
=7/63
simplify by 7
=1/9


7) (9/10)/6

= 9/10 ÷ 6
to divide fractions, multiply by the reciprocal/inverse of 6

= 9/10 * 1/6
multiply numerators; multiply denominators

= (9*1)/(10*6)
= 9/60
simplify by 3
= 3/20


ANSWER: 1) 20; 4) 1/9; 7) 3/20

Hope this helps! :)
3 0
3 years ago
I need to know the answer ASAP thank you
ElenaW [278]

Answer:

Step-by-step explanation:

3 0
3 years ago
For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
Elina [12.6K]

Answer:

<em>C.</em> (5-\frac{1}{2})^6

Step-by-step explanation:

Given

15(5)^2(-\frac{1}{2})^4

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

Sum = 2 + 4

Sum = 6

Each term of a binomial expansion are always of the form:

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

Where n = the sum above

n = 6

Compare 15(5)^2(-\frac{1}{2})^4 to the above general form of binomial expansion

(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......

Substitute 6 for n

(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

By direct comparison of

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

and

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

We have;

^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4

Further comparison gives

^nC_r = 15

a^{n-r} =(5)^{6-4}

b^r= (-\frac{1}{2})^4

[Solving for a]

By direct comparison of a^{n-r} =(5)^{6-4}

a = 5

n = 6

r = 4

[Solving for b]

By direct comparison of b^r= (-\frac{1}{2})^4

r = 4

b = \frac{-1}{2}

Substitute values for a, b, n and r in

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

Solve for ^6C_4

(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em>(5-\frac{1}{2})^6<em />

3 0
3 years ago
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