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LiRa [457]
3 years ago
6

Find the inverse of f(x)=5x-2

Mathematics
1 answer:
kompoz [17]3 years ago
5 0

Answer:

f^{-1}(x) = \frac{x+2}{5}

Step-by-step explanation:

Let y = f(x) and rearrange making x the subject

y = 5x - 2 ( add 2 to both sides )

y + 2 = 5x ( divide both sides by 5 )

\frac{y+2}{5} = x

Change y back into terms of x

f^{-1} (x) = \frac{x+2}{5}

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

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8-2+(12÷2)

Hope this helps :)
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1 5/6 because you have to first find half of 3 which is 1 1/2 then you have to find half of 2/3 which is 1/3 then you have to find a common denominator then add. After that simplest form.
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Which is not a property of countercurrent multiplication?
laiz [17]

Answer:

It is opposed by the vasa recta.

Step-by-step explanation:

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