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gtnhenbr [62]
2 years ago
12

What number between 121 and 149 is exactly divisible by both 3 and 5

Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
4 0

Answer:

135

Step-by-step explanation:

135 ÷ 5 = 27

135 ÷ 3 = 45

hope this helps

Komok [63]2 years ago
3 0

Answer:

135

Step-by-step explanation:

135 by 3 is 45

by 5 is 27

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If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

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2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

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Then we have:

a = 8, b = 3, c = -5

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A, the graph is shown

Step-by-step explanation:

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