What number between 121 and 149 is exactly divisible by both 3 and 5
2 answers:
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Question: Simplify 
.
First off, you <em>never</em> want square roots on the bottom of a fraction, so let's multiply both sides by
to get rid of it. All we have to do from there is simplify!
First off, you <em>never</em> want square roots on the bottom of a fraction, so let's multiply both sides by
Answer:
x = ±2, 3 are the critical points of the given inequality.
Step-by-step explanation:
The given inequality is
To find the critical points we will equate the numerator and denominator of the inequality to zero.
For numerator,
(x - 2)(x + 2) = 0
x = ±2
For denominator,
x² - 5x + 6 = 0
x² - 3x -2x + 6 = 0
x(x - 3) -2(x - 3) = 0
(x - 3)(x - 2) = 0
x = 2, 3
Therefore, critical points of the inequality are x = ±2, 3 where the sign of the inequality will change.
