What is the answer to this problem?

The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of

Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

6 0

2 years ago

In each triangle p is the circumcenter use circumcenter theorem to solve for the givin values

timurjin [86]

Answer:

Circumcenter theorem states that the vertices of the each triangle are equidistant from the circumcenter.

As per the statement:

It is given that: P is the circumference

From the given figure:

CP = 12 units.

then;

by circumcenter theorem;

AP= BP =CP = 12 units.

Next find the value of AB:

Labelled the diagram:

AD = 11 units

then;

AB = AD+DB

Since: AD=DB [You can see it from the given figure]

then;

AB = 2AD = 2(11) = 22 units

Therefore, the value of BP and AB are: 12 units and 22 units

4 0

2 years ago

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Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t

alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

6 + 6 = 12 seeds, which means that $N = 12$

6 treated, which means that $k = 6$

Five sprouted, which means that $n = 5$

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076$

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0

2 years ago

For each of the sequence below identify whether there is a common ratio. If there is identity what it is. If there is not a comm

vfiekz [6]

yes

1.-3

2.3

3.10

4.2

5.3

6 0

3 years ago

Round to the nearest whole number to estimate

LUCKY_DIMON [66]

If you round you get 50

8 0

2 years ago

Read 2 more answers