Answer:
Amounts in the intervall ![130 \leq c \leq 230](https://tex.z-dn.net/?f=130%20%5Cleq%20c%20%5Cleq%20230)
Step-by-step explanation:
We will take the variables c and s, where
c = amount to spend that month
s = savings of the month.
Since each month we save at least 100, we know that
![0 \leq s \leq 100](https://tex.z-dn.net/?f=0%20%5Cleq%20s%20%5Cleq%20100)
Moreover, we earn $250 per month and we spend $20 in a kayaking club, which tells us that
![250=20+s+c](https://tex.z-dn.net/?f=250%3D20%2Bs%2Bc)
and so
![230-s=c](https://tex.z-dn.net/?f=230-s%3Dc)
By multiplying by -1, the first inequality also tells us that
![-100 \leq -s \leq 0](https://tex.z-dn.net/?f=-100%20%5Cleq%20-s%20%5Cleq%200)
Consequently by adding 230 to the inequality, we get that
![230-100 \leq 230-s \leq 230\\\\\Rightarrow 130\leq c \leq 230](https://tex.z-dn.net/?f=230-100%20%5Cleq%20230-s%20%5Cleq%20230%5C%5C%5C%5C%5CRightarrow%20130%5Cleq%20c%20%5Cleq%20230)
Your question is a little bit unclear but I'll try to help:
When quantity increases, we can calculate it's percent increase using equation.
PERCENT INCREASE= (new amount−original amount)/original amount}
<span>
You can also multiply it by 100% go tet percent value.
</span>When quantity decreases, you can calculate it's percent increase using equation.
PERCENT DECREASE=(original amount−new amount)/original amount
You can also multiply it by 100% go tet percent value.<span>
</span>
Answer:
I will let it lead me down the paths ahead of me. I never in my life thought that Dylan McKay would be a major influence on my growth as a person. But that's the way it seems to be going right now. So wish me luck, and may the bridges I've burned light the way.
this is not that long but I tried
You have a mortgage payment of 1248.90. using proportions, what is the minimum amount you must have in realized income per month to keep your housing expense in the acceptable range