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MA_775_DIABLO [31]
2 years ago
11

PLS HELP i need this questions fast

Mathematics
1 answer:
lora16 [44]2 years ago
7 0
D- this should be correct because it explains the possible way of them matching even though DEF is bigger
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Daniel dives into a swimming pool. The height of his head is represented by the function h(t) = -8t2 - 28t + 60, where t is the
8_murik_8 [283]
So, h(t) is how far is Daniel's head from the surface of the water, namely the surface itself is when the height is nill, so his head is at the surface and the height of it is just 0, thus h(t)  = 0.  Namely, what is "t" when h(t) is 0?

\bf h(t)=-8t^2-28t+60\implies \stackrel{h(t)}{0}=-8t^2-28t+60
\\\\\\
0=-2t^2-7t+15\implies 2t^2+7t-15=0\implies (2t+3)(t-5)=0
\\\\\\
\begin{cases}
2t+3=0\implies 2t=-3\implies &t=-\frac{3}{2}\\\\
t-5=0\implies &\boxed{t=5}
\end{cases}

clearly the seconds cannot be a negative unit, so is not -3/2.
6 0
3 years ago
Zack and his dad baked some cupcakes for his class. They put 6 cups on each of 8 plates. How many cupcakes did they put on the p
kolezko [41]

Answer:

48 cupcakes were put on the plates.

Step-by-step explanation: 6 x 8 = 48

I hoped this answer helped you solve your problem!

Sincerely, iloveyouplease123ims

8 0
3 years ago
What is the slope of this line? <br> A.) −3/4<br> B.) 3/4<br> C.) −4/3<br> D.) I don't know.
alina1380 [7]
A: -3/4
Rise/Run
3 is the rise
4 is the run
3 0
2 years ago
Read 2 more answers
A recipe requires 3/4 of a cup of flour.
nalin [4]

Answer:

<h2>168.75 g</h2>

Step-by-step explanation:

the required mass of flour = (3÷4)×225 = 168.75

8 0
3 years ago
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x. 
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
= 2x (27 - 3x^2) 
= 54x - 6x^3 
For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

d²A/dx² = - 36x < 0 for x = √3 
=> maximum area 
= 54(√3) - 6(√3)^3 
= 54√3 - 18√3 
= 36√3. 
4 0
3 years ago
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