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Lapatulllka [165]
3 years ago
13

Mr. Austin is driving 390 miles to visit the Gateway Arch in St. Louis, Missouri. He dries at an average rate of 65 miles per ho

ur. How much time will it take Mr. Austin to get to the arch?
Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

the time needed to get to the arch is 6 per hour

Step-by-step explanation:

The computation of the time needed to get to the arch is shown below:

As we know that

Speed = distance ÷ time

where,

Speed is 65 miles per hour

And, the distance is 390 miles

So, the time is

= 390 ÷ 65

= 6 per hour

Hence, the time needed to get to the arch is 6 per hour

We simply applied the above formula so that the correct value could come

And, the same is to be considered  

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3 years ago
Are the irrational numbers closed under addition?
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Irrational numbers are not closed under addition.

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>

Lastly, look at ΔBHD.  Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.

BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



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