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Varvara68 [4.7K]
2 years ago
15

Ulian pays $120 for soccer shoes that are on sale for 20% off from a specialty store. At a discount store, the same shoes cost $

42 less than they cost at the specialty store. They are on sale for 61% off. Complete the proportions below. Highlight in yellow the sale price of the shoes at the discount store. Highlight in orange the original price of the shoes at the discount store.
Mathematics
1 answer:
makvit [3.9K]2 years ago
7 0

Answer:

Sales price = $78

Original price = $61

Step-by-step explanation:

Ulian bought the shows for $120 at a specialty store. This discount store had it at $42 less. The price at the discount store is therefore:

= 120 - 42

= $78

The shoes at the discount store are 61% off and the discounted price is $78. Assume the original price is x. The original price will be:

x - (x * 61%) = 78

x - 0.61x = 78

0.39x = 78

x = 78/0.39

x = $200

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(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

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Step-by-step explanation:

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So it would be b= 1/5+7

The slopes has to be different and you don't have to worry about the "+7"

Reply if you have any questions


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