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Inessa05 [86]
3 years ago
8

Solve: 6(8+7a)≤132 I really need hellpppp

Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

a ≤ 2

Step-by-step explanation:

Simplify both sides of the inequality

42a + 48 ≤ 132

Subtract 48 from both sides

42a + 48 − 48 ≤ 132 − 48

42a ≤ 84

Divide both sides by 42

42a/42 ≤ 84/42

a ≤ 2

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Given: a||b, m∠ 6=128° Find: m∠1, m∠3
goldfiish [28.3K]

Answer:

m∠1 = 52°

m∠3 = 52°

Step-by-step explanation:

Step 1:

Since b is a straight line and is transversed by line m and we are given m∠6 = 128°, we can find m∠5, which is 180 - m∠6, giving us 52° for ∠5.

Step 2:

Because a and b are parallel, m∠5 and the m∠1 are the same, so we have m∠1 = 52° as one of our answers needed

Step 3: Because ∠3 is vertical to ∠1, we can use the vertical angles theory and say that m∠1 is equal to m∠3. Therefore, m∠3 = 52°

5 0
3 years ago
Find the other endpoint of the line segment if:
Vesna [10]

Answer:

<em>( - 15, - 16 ) </em>

Step-by-step explanation:

Coordinates of midpoint are ( \frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )

( - 5 + x ) / 2 = - 10 ⇒ x = - 15

( 4 + y ) / 2 = - 6 ⇒ y = - 16

<em>( - 15, - 16 )</em>

5 0
3 years ago
The school board has approved the addition of a new sports team at your school.
motikmotik

Answer:

210

Step-by-step explanation:

1: Part/whole=%/100

2: 100-5=95

3: 3150/30=$105 uniforms.

Answer: $210

<em><u>Hope this helps.</u></em>

6 0
3 years ago
The length of a rectangle is 5 in. more than 3 times its width. The quadratic function f(x) = x(3x + 5) represents the area of t
saveliy_v [14]
F(x)=x(3x+5)
or
f(x)=3x²+5x
Here the domain in general is: -∞<x<∞
But the length of the rectangle cannot be negative, therefore the domain is all real numbers greater than zero.

Option D is correct.


5 0
3 years ago
Read 2 more answers
2x+y=8<br> y+3z=5<br> z+2w=1<br> 5w+3x=9<br><br> what is x,y,z,w
notka56 [123]

Answer:

Systems of equations:

x=3

y=2

z=1

w=0

5 0
2 years ago
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