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stellarik [79]
3 years ago
6

I need help plz cmon

Mathematics
1 answer:
PolarNik [594]3 years ago
7 0

Answer: 84

Step-by-step explanation:

4 x 21 is 84 a fraction can be simplified and be a whole number so if 84 divided by 4 it will be 21 if you want to write it as a fraction it will be 21/1 which is equal to 21

Did it help? :)

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Find the value of (a+b)^2 if a^2+b^2=10 and ab=3
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Step-by-step explanation:

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Four bags of dry dog food plus 9.5 pounds of dry cat food weigh 17.5 pounds in all. How many pounds does each bag of dog food we
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2

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Tina practiced piano for 15 hours last month and 45 hours this month A. Use multiplication to write a statement comparing the ho
KonstantinChe [14]

Answer: The answer is (a) 3 × x = y   and   (b) x + x + x = y.

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x = 15   and   y = 45.

We can write the relation between 'x' and 'y' in two forms as follows -

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(b) Addition form : 15 +15 +15 = 45  implies x + x + x = y.

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4 0
3 years ago
Research suggests that about 60% of CSU graduates started at a community college. In random samples of 100 CSU graduates, the pe
Nesterboy [21]

Answer:

The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>p</em> = 0.60

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As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.

The distribution of sample proportion is \hat p\sim N(0.60, 0.049^{2}).

Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:

P(|\hat p-\mu_{\hat p}|=0.05)=P(-0.05

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Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

8 0
3 years ago
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