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Lady_Fox [76]
3 years ago
9

Help plzzzz what is the value of x

Mathematics
2 answers:
harina [27]3 years ago
5 0
Answer is x=13.
basically you put them together and make them =180
Andre45 [30]3 years ago
4 0

Answer:

the interior angles of any triangle are equal to 180.

In other words m<BAC + m<ABC + m<ACB = 180.

Therefore,

(3x-1) + (8x-35) + (6x-5) = 180

Now that we have an equation, we can solve for x:

(3x-1) + (8x-35) + (6x-5) = 180

Combine like terms:

3x+8x+6x-1-35-5

17x-41 = 180

Add 41 to each side:

17x-41+41 = 180+41

17x=221

Divide by 17 on both sides:

x=13

Now to check if this is correct we need to plug in x for each equation and the three numbers combined should equal 180.

3x-1

3(13)-1

38

6x-5

6(13)-5

78-5

73

8x-35

8(13)-35

104-35

69

Now we just add them to see if they equal 180

38+73+69 = 180

x=13 is valid

Step-by-step explanation:

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Step-by-step explanation:

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iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

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Answer:

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Step-by-step explanation:

You observe that the coefficient in the second equation are all multiples of 3. Dividing that equation by -3 gives the two equations ...

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Which shows a set of three equivalent decimals?
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