I’m pretty sure the distance would be (2,5)
Answer:
t = 1, but please check to see if I correctly interpreted your formatting.
Step-by-step explanation:
The format of the question is too confusing.
I'll assume this is the equation to be solved:
<u>16−2t=t+9+4t</u>
<u></u>
16−2t=t+9+4t
16-9 = t + 2t + 4t
7 = 7t
t = 1
In triangle ABC,
AC = 12/ (sin30) = 12 / (1/2) = 24
DC = 24-x
DB = DC tan 30 = (24-x) tan30 <span>=(24−x)/</span><span>√3
</span>
In triangle ADB using Pythagorean Theorem<span><span>x2</span>+((24−x)/<span>√3</span><span>)2</span>=<span>12^2</span></span><span><span>x2</span>+(24−x<span>)^2</span>/3=<span>12^2</span></span><span>3<span>x2</span>+(24−x<span>)^2</span>=432</span><span>4<span>x2</span>−48x+576=432</span><span>4<span>x2</span>−48x+144=0</span><span><span><span>x2</span>−12x+36=0
x1 = x2 =6
AD = AC - DC = 24- (24-x) = 6</span></span>
Hope you are able to understand the solution. :-D
