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Korvikt [17]
3 years ago
14

Help me please:) will very much appreciate it

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0
1. 18
2. 7/4

Here is my answer, hope to help you
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A bottle of water 2/3 full. You drink 3/4 of the water. Use a model to find the portion of the bottle of water that you drink .
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You drunk 1/1 of the bottle of water
6 0
3 years ago
Read 2 more answers
INDEPENDENT PRACTICE
nydimaria [60]
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8 0
2 years ago
Four speed skaters, Marco
dmitriy555 [2]

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:
Marina CMI [18]
<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

                                 Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

                    f(-x)=-f(x)

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

                      f(-x)=f(x)

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function  is symmetric about the origin.</em>

7 0
3 years ago
Which expression is equivalent to the following complex fraction?
tatyana61 [14]
\dfrac{\frac{x}{x-3}}{\frac{x^2}{x^2-9}}=\dfrac{x(x^2-9)}{(x-3)x^2}=\dfrac{x(x+3)(x-3)}{(x-3)x\cdot x}=\dfrac{x+3}{x}

Answer C.

3 0
3 years ago
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