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2 years ago

20 POINTS PLEASE HELP

Mathematics

1 answer:

aleksley [76]2 years ago

8 0

Answer:

Step-by-step explanation:

Exponents of the same base add

A. 2^4 • 2^3 = 212

2^7 = 128 ≠ 212

B. 3^3 • 3^6 > 3^8

3^9 > 3^8

C. 4^2 • 4^2 > 4^4

4^4 = 4^4

D. 5^5 • 5^2 = 5^10

5^7 ≠ 5^10

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the dashed triangle is a dilation image of a solid triangle with the center at the organ is the dilation an enlargement or reduc

Kruka [31]

The image is inverted. The figure and the image have a common point. The common point is the center of dilation.

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3 years ago

A cell phone company charges a flat fee of 20 dollars plus 3 cents a call. What is the total bill if there was a total of 200 ca

34kurt

Answer:

Total Bill = 4006 dollars

Step-by-step explanation:

A cell phone company charges a flat fee of 20 dollars plus 3 cents a call.

If there was a total of 200 calls for the month, the total charge by the cell phone company will be.

Let me convert all to cent first

100 cent = 1 dollar

20 dollar =20 *100

29 dollar = 2000 cent

Charge by the company for a call is 2003 cent

Let me put down the equation.

1 call = 2003 cent

200 calls =( 200 calls* 2003cent)/1 call

200 calls = 200 * 2003cent

200 calls = 400600 cent

Let's convert back to dollar

100 cent = 1 dollar

400600 cent = 400600/100

400600 cent = 4006 dollars

8 0

2 years ago

Her the

Otrada [13]

Answer:

13. m∠MN + m∠NMP = m∠MP.

14. m∠NMP - m∠OMP = m∠NMO.

15. x = 3 + y and -2y + 3 < -1 : Given

16. x > y : x = 3 + y

17. -2y < -4 : -2y < -4

18. y > 2 : y > 2

19. x > 2 : x = 3 + y and y > 2

------------------------------------------

5 0

2 years ago

Help need to do it the equation and the real world problem

melomori [17]

A volleyball uniform costs $13 for the shirt, $11 for pants, and $8 for socks. Write two equivalent expressions for the total cost of 12 uniforms. Then find the cost.

Write an expression for the cost of 1 uniform, add $13, $11 and $8 .

$13+$11+$8

Write an expression for the cost of 12 uniforms, multiply 12 by the cost of 1 uniform.

12($13+$11+$8)

Simplify using the distributive property.

=12⋅13+12⋅11+12⋅8=156+132+96

Now Add.

=384

So, the total cost of 12 uniforms is $384 .

3 0

3 years ago

Places A and B are 100km apart from each other on a highway. A car starts from A and another from B at the same time. If they mo

Mashutka [201]

Answer:

Speed of the first car = x = 35km/hr

Speed of the second car = 25km /hr

Step-by-step explanation:

The calculation of speeds of the cars is given below:-

Assume that the speed of the 1st car which is opening from A = x km/hr

and assume the Speed of the 2nd car which is starting from B

= y km/hr

As we know that

Time = Distance ÷ Speed

So, the distance lies between two places i.e. A and B are

80km d = 80 km

1. now when the car moves in the similar direction

So, the corresponding speed of them = (x + y)km/hr

Time = 8hr

d = 80km

$8 = \frac{80}{(x + y)}\\\\x + y = \frac{80}{8}\\\\x + y = 10 ..... (i)$

2. when two cars moving in the inverse direction,

So, the corressponding speed = (x - y) km / hr

Time = 1 hr 20 minutes

That means

= (1 + 20 ÷ 60) hr

= (80 ÷ 60)

= 4/3 hr

d = 80km

Now

4 ÷ 3 = 80 ÷ (x -y)

x -y = (80 × 3) ÷ 4

x - y = 60 ..... (ii)

Now, we will sum equation 1 and equation 2 we will get

2x = 70

x = 35

now, Put x = 35 in (i) we will get

y = 25

Speed of the first car = x = 35km/hr

Speed of the second car = 25km /hr

8 0

3 years ago