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malfutka [58]
3 years ago
14

Write the word sentence as an inequality. Then solve the inequality.

Mathematics
2 answers:
aleksley [76]3 years ago
6 0
The answer is 4x>_-12. the underscore is the line under the “>”
Akimi4 [234]3 years ago
6 0

Answer:

-3

Step-by-step explanation:

-12 divided by 4 -3

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There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red
madam [21]

Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =\frac{12}{20}

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =\frac{8}{19}

So, the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag =\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}

Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

3 0
3 years ago
Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
ra1l [238]
Earnings=20% of sales+7.5h+40

coeficinets are 7.5 and 0.2
vraiables are h and s
constant is 40

B. if h=25 and s=30 input,
7.5*25+0.2*300+40=$287.50


C
new equation is 9h+0.2s+40
coefienct woud be 9 and 0.2
variable is h and s
constant is 4

7 0
3 years ago
Find the square root of each.
DIA [1.3K]
169=13
144=12
Hope this helps and please give brainliest!
8 0
2 years ago
If a statistic used to estimate a parameter is such that the mean of its sampling distribution is equal to the actual value of t
zimovet [89]
I think the correct answer from the choices listed above is the third option. <span>If a statistic used to estimate a parameter is such that the mean of its sampling distribution is equal to the actual value of the parameter, then it is a biased estimator. Hope this answers the question.
</span>
6 0
3 years ago
Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced
Sati [7]

Answer:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

Step-by-step explanation:

\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls},(denoted \:W_1, W_2, \:and\: W_3)

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and  its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

The tree diagram of this event is also attached.

6 0
3 years ago
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