A=(2,4); B=(3,9); C=(4,1)
A'=(4,-2); B'=(9,-3); C'=(1,-4)
All the points P=(x,y) change to P'=(y,-x), this corresponds to a rotation counterclockwise about the origin, then:
Answer: Triangle ABC is
First box: rotated counterclockwise
Second box: 90° about the origin
to form triangle A'B'C'
The charter bus will take 7 hours to get there, so they will get there at 1pm. Her parents would actually get there before the bus because it's only going to take 5 hours.
Answer: 429.88
Step-by-step explanation:
The first 40 hours is at 9.50
40 *9.50 =380
The remaining hours is at 9.50 * 1.5 or 14.25
43.5 -40 = 3.5
3.5 * 14.25
49.875 = 49.88 ( rounding to the nearest cent)
Add together
380+49.88 =429.88
Answer:
D
Step-by-step explanation:
Using the Cosine rule to find AC
AC² = BC² + AB² - (2 × BC × AB × cosB )
= 18² + 12² - ( 2 × 18 × 12 × cos75° )
= 324 + 144 - 432cos75°
= 468 - 111.8
= 356.2 ( take the square root of both sides )
AC = 
≈ 18.9
-----------------------------------------
Using the Sine rule to find ∠ A
= 
( cross- multiply )
18.9 sinA = 18 sin75° ( divide both sides by 18.9 )
sinA = 
, then
∠ A = 
( ) ≈ 66.9°
Answer: Time it took her to get to the school is 0.6 hours
The distance of the school from their home is 27 miles
Step-by-step explanation:
Mrs Dang drove her daughter to school at the average speed of 45 miles per hour.
Let x miles = distance from the school to their home.
Distance = speed × time
Time = distance / speed
Time used in going to school will be
x/45
She returned home by the same route. This means that distance back home is also x miles.
She returned at an average speed of 30 miles per hour.
Time used in returning home from school will be x/30
x/45
If the trip took one half hour, then the time spent in going to school and the time spent in returning is 1 1/2 hours = 1.5 hours. Therefore
x/30 + x/45 = 1.5
(15x + 10x) /450 = 1.5
15x + 10x = 450 × 1.5 = 675
25x = 675
x = 675/25 = 27
Time it took her to get to the school will be x/45
= 27/45 = 0.6 hours
