Multiply 2 1/4, 1 3/5 and 2 1/3 together! It would be easier to turn these mixed fractions into improper fractions.
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Answer: 144</h3><h3>
Step-by-step explanation:</h3><h3 />
Since, the first 9 multiple of 4 starts from 0 are,
0, 4, 8, 12, 16, 20, ................
Which is an AP,
Having the first term, 
And, the successive difference, d = 4,
Since, the sum of the n term of an AP,
![S_n = \frac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D)
Hence the sum of 9 term of the above AP,
![S_9 = \frac{9}{2}[2\times 0 + (9-1)\times 4]](https://tex.z-dn.net/?f=S_9%20%3D%20%5Cfrac%7B9%7D%7B2%7D%5B2%5Ctimes%200%20%2B%20%289-1%29%5Ctimes%204%5D)



There are 10 letters in the set {a, b, c, d, e, f, g, h, i, j} which is the pool of letters to choose from when making these three letter codes.
We have 10 choices for slot 1
Then 9 choices for slot 2. This is because we can't reuse the choice for slot 1
Then 8 choices for slot 3
Overall, there are 10*9*8 = 90*8 = 720 different permutations
Answer: 720
Note: you can use the nPr permutation formula with n = 10 and r = 3 to get the same answer