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DochEvi [55]
3 years ago
10

The circumference of the hub cap of a tire is 83.96 centimeters. Find the area of this hub cap. Use 3.14 for . Use pencil and pa

per. If the circumference of the hub cap were​ smaller, explain how this would change the area of the hub cap.
Mathematics
1 answer:
Bess [88]3 years ago
5 0

Answer:

Area = 561.2485 square centimeter

If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.

Step-by-step explanation:

As we know the circumference of a circle is 2\pi r

The radius of the hub cap needs to be devised to determine the area

83.96 = 2* 3.14*r

r = \frac{83.96}{2*3.14}

r = 13.37 centimeters

Area of the hub cap = \pi r^{2}

Substituting the devised value of r in the above equation, we get -

3.14 * 13.37^2\\

561.2485 square centimeter

If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.

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I would say A. is the correct answer. Definitely a weird one. Hope this helps!
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4 years ago
In monitoring lead in the air after the explosion at the battery factory, it is found that the amounts of lead over a 6 day peri
liubo4ka [24]

Answer:

The margin of error that corresponds to a 95% confidence interval is 4.96.

Step-by-step explanation:

We have the standard error(which is the same as the standard deviation of the sample), so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. There are 6 days, so

df = 6 - 1 = 5

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975([tex]t_{0.975}). So we have T = 2.5706

The margin of error is:

M = T*s = 2.5706*1.93 = 4.96

The margin of error that corresponds to a 95% confidence interval is 4.96.

3 0
4 years ago
The width of a rectangular card is 2 cm lekss than the Tength. The area is 15 cm. Find the length and
Yuri [45]

Answer:

Step-by-step explanation:

Area A = 15square cm

Length L = x

Width w = x - 2

Area = L × w

15 = x(x - 2)

15 = x^2 -2x

x^2 -2x - 15 = 0

Solving by factorization

x^2 - 5x + 3x - 15 = 0

(x^2 -5x) + (3x -15) = 0

x(x - 5) + 3(x - 5) = 0

(x + 3)(x - 5) = 0

(x + 3) = 0 or (x - 5) = 0

x = -3 or 5

Since x can't be negative therefore x is 5cm

Length = 5cm

Width = 5-2 = 3cm

5 0
3 years ago
On a map, the distance between two towns is 2.5 inches, and 1 inch represents 6 miles. What is the actual distance between the t
White raven [17]
X=6.2*20
X=124 MILES BETWEEN THESE 2 TOWNS.
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4 years ago
A line segment has the endpoint T (2, 4) and the Midpoint of (3, 6.5) Find thecoordinates of the other point B. Write it as a po
Evgen [1.6K]

We have a segment, for which we know one endpoint T=(2,4) and the midpoint M=(3, 6.5).

We have to find the other endpoint, lets call it S.

Both for the x-coordinates and y-coordinates the distance in each axis from T to M (TM) has to be equal to the distance M to S (MS).

Then, if we look at the x-axis, we have that the distance is TMx=2-3=-1.

Then, S has to be one unit above M: the x-coordinate of S is xS=4.

We do the same for the y-axis. The distance TMy is TMy=4-6.5=-2.5.

Then, S has to be 2.5 units above M: the y-coordinate of S is yS=(6.5+2.5)=9.

The coordinates of S are (4,9).

Graph:

4 0
1 year ago
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