I would say A. is the correct answer. Definitely a weird one. Hope this helps!
Answer:
The margin of error that corresponds to a 95% confidence interval is 4.96.
Step-by-step explanation:
We have the standard error(which is the same as the standard deviation of the sample), so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. There are 6 days, so
df = 6 - 1 = 5
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.5706
The margin of error is:
M = T*s = 2.5706*1.93 = 4.96
The margin of error that corresponds to a 95% confidence interval is 4.96.
Answer:
Step-by-step explanation:
Area A = 15square cm
Length L = x
Width w = x - 2
Area = L × w
15 = x(x - 2)
15 = x^2 -2x
x^2 -2x - 15 = 0
Solving by factorization
x^2 - 5x + 3x - 15 = 0
(x^2 -5x) + (3x -15) = 0
x(x - 5) + 3(x - 5) = 0
(x + 3)(x - 5) = 0
(x + 3) = 0 or (x - 5) = 0
x = -3 or 5
Since x can't be negative therefore x is 5cm
Length = 5cm
Width = 5-2 = 3cm
X=6.2*20
X=124 MILES BETWEEN THESE 2 TOWNS.
Hope this helps you:)
We have a segment, for which we know one endpoint T=(2,4) and the midpoint M=(3, 6.5).
We have to find the other endpoint, lets call it S.
Both for the x-coordinates and y-coordinates the distance in each axis from T to M (TM) has to be equal to the distance M to S (MS).
Then, if we look at the x-axis, we have that the distance is TMx=2-3=-1.
Then, S has to be one unit above M: the x-coordinate of S is xS=4.
We do the same for the y-axis. The distance TMy is TMy=4-6.5=-2.5.
Then, S has to be 2.5 units above M: the y-coordinate of S is yS=(6.5+2.5)=9.
The coordinates of S are (4,9).
Graph: