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erastovalidia [21]
3 years ago
15

Any0ne know the answer for math?

Mathematics
1 answer:
Romashka [77]3 years ago
4 0

Answer:

64p⁶q⁶/27

Step-by-step explanation:

(4p⁴q⁴/3p²q²)³

= (4p²q²/3)³

= 64p⁶q⁶/27

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3 years ago
Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1
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Answer:

-2,\ -1,\ -\dfrac{1}{2},\ 3.

Step-by-step explanation:

Consider polynomial 2x^4+x^3-14x^2-19x-6.

If x=-2 is its zero, then you can divide the polynomial 2x^4+x^3-14x^2-19x-6 by x+2 and get

2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).

If x=-1, then the polynomial 2x^4+x^3-14x^2-19x-6 can be rewritten as

2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).

The quadratic polynomial has roots

x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.

Then the polynomial 2x^4+x^3-14x^2-19x-6 has zeros -2,\ -1,\ -\dfrac{1}{2},\ 3.



7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28-2a%5E%7B4%7Db%5E%7B2%7D%29%5E3" id="TexFormula1" title="(-2a^{4}b^{2})^3" alt="(-2a^{4}b^{
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Answer:

-8a^12b^6

Step-by-step explanation:

multiply each term with the power

4 0
3 years ago
Been here for hours please help me
mezya [45]

Answer:

free points

Step-by-step explanation:

8 0
3 years ago
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