Set the whole expression = to 0 and solve for x.
3x^(5/3) - 4x^(7/3) = 0. Factor out x^(5/3): x^(5/3) [3 - 4x^(2/3)] = 0
Then either x^(5/3) = 0, or 3 - 4x^(2/3) = 0.
In the latter case, 4x^(2/3) = 3.
To solve this: mult. both sides by x^(-2/3). Then we have
4x^(2/3)x^(-2/3) = 3x^(-2/3), or 4 = 3x^(-2/3). It'd be easier to work with this if we rewrote it as
4 3
--- = --------------------
1 x^(+2/3)
Then
4
--- = x^(-2/3). Then, x^(2/3) = (3/4), and x = (3/4)^(3/2). According to my 3 calculator, that comes out to x = 0.65 (approx.)
Check this result! subst. 0.65 for x in the given equation. Is the equation then true?
My method here was a bit roundabout, and longer than it should have been. Can you think of a more elegant (and shorter) solution?
Answer:
55
Step-by-step explanation:
bisect means to cut in half so it is half of 110 so it is 55
Answer:
addition
Step-by-step explanation:
Example: 5^1 * 5^3= 5^4
Answer
so there are 7 singing acts and 5 comedy acts.
Step-by-step explanation:
Let x= number of singing acts.
Let y= number of comedy acts.
We will take x+y=12 as our first equation, as there are 12 shows in total. We will take 5x+3y=50 as our second equation as there are 50 total minutes, and singing acts are 5 mins and comedy acts are 3 mins.
We solve x+y=12
Y=-x+12
We know y=-x+12, so we will substitute that for the y in the second equation.
1. Substitute 5x+3(-x+12)=50
2. Distribute 5x-3x+36=50
3. Solve 2x+36=50
2x=14
X=7
Now that we have found x, we will find y by substitute the x in 5x+3y=50 with the value, 7, that we found for x.
5(7)+3y=50
35+3y=50
3y=15
Y=5
Answer:
10/9
Step-by-step explanation:
