Answer:
78% (to the nearest tenth)
Step-by-step explanation:
Volume of a cube = (length )³
Let the length of the cube = y
Original volume = y³
if the length is decreased by 40%, then new length = 1- (40% of y)
= 1-0.4y
= 0.6%
New volume (after decreasing the length) = (0.6y)³
= 0.216y³
% Volume decrease = (Original volume - New volume)/Original Volume x 100%
= (y³ - 0.216y³)/ y³ x 100%
= 0.784y³/y³ x 100%
=78.4%
≈78%
<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
(A) 
(b) 
(c)
(d) 
Step-by-step explanation:
We have given expression and we have to simplify the expression using exponent property
(A) 
So 
(b) 
So 
(c) 
So 
(d) 
Answer:
|x-99|<3
Step-by-step explanation:
|x-99|<3
Answer: The average velocity of the object over the time interval [3,6] is 20.
Step-by-step explanation:
Since we have given that
s(3) = 156
s(6) = 216
We need to find the average velocity over the time interval [3,6].
So, average velocity becomes
Hence, the average velocity of the object over the time interval [3,6] is 20.
