Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Yes, she is correct
1/2 + 1/2 = 1 or 0.5 + 0.5 = 1 so half of a wall plus half of a wall equals one hole wall.
That's as simple as I can put it mathematical reasoning. I hope this helps
Answer:
4
Step-by-step explanation:
x^2/ y^4
Let x=8 and y=2
8^2 / 2^4
PEMDAS says powers first
64 / 16
Divide next
4
Answer:
9
Step-by-step explanation:
V=pi (r squared) (h/3)
75pi = 25pi (h/3)
Divide both sides by 25 pi
3= h/3
Multiply both sides by 3
h=9
Answer:
To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations. I hope this helped!
