Answer:
5^3 y^5
125 y^5
Step-by-step explanation:
5y^3/(5y)^-2
Distribute the exponent in the denominator
5y^3/(5 ^-2 y^-2)
A negative exponent in the denominator brings it to the numerator
5y^3 5 ^2 y^2
Combine like terms
5 * 5^2 * y^3 5^2
We know that a^b * a^c = a^(b+c)
5^(1+2) * y^( 3+2)
5^3 y^5
125 y^5
The sum of the ball's kinetic energy and potential energy remains the same. as the ball rolls from point A to E.( if there is no friction between the ball and the ground).
based on the law of mechanical energy's conservation, the sum of both kinetic and potential energies i.e. the total amount of mechanical energy remain conserved even in the absence of dissipative forces ( friction or air resistance) in a bound system.
the kinetic energy is when ball goes downward but potential energy decreases and reverse happens when ball goes up. but in these case, the sum energy would be constant one.
The ball would not change the energy.
To learn more about kinetic energy
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SPJ9
The decimal representation for 4/5 would be,
0.8
Hope it helped. It's all I could do.
Answer:
We get the final answer of -4x + 6
Step-by-step explanation:
Let's simplify step-by-step.
2x −3(2x−2)
Distribute:
= 2x+ (−3)(2x) + (−3)(−2)
= 2x+ −6x + 6
Combine Like Terms:
= 2x + −6x + 6
= (2x + −6x) + (6)
= -4x + 6
