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gulaghasi [49]
3 years ago
15

Ten field hockey teams are competing in a tournament. Only the top three teams will be recognized as the first place, second pla

ce and third place winners. In how many ways could the ranking of the top three teams occur?
Mathematics
1 answer:
DedPeter [7]3 years ago
3 0

Answer:

The ranking of the top three teams could occur in 720 ways.

Step-by-step explanation:

The order in which the teams are ranked is important, that is, for example, Oilers, Flames and Canucks is a different outcome of Oilers, Canucks and Flames. This means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In how many ways could the ranking of the top three teams occur?

Three teams from a set of 10. So

T = P_{(10,3)} = \frac{10!}{7!} = 720

The ranking of the top three teams could occur in 720 ways.

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Add an intersection the red light times normally distributed by the mean of three minutes and a standard deviation of .25 minute
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95% of red lights last between 2.5 and 3.5 minutes.

<u>Step-by-step explanation:</u>

In this case,

  • The mean M is 3 and
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Assume the bell shaped graph of normal distribution,

The center of the graph is mean which is 3 minutes.

We move one space to the right side of mean ⇒ M + SD

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Again we move one more space to the right of mean ⇒ M + 2SD

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Move one space to the left side of mean ⇒ M - SD

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Step-by-step explanation:

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