Question

I NEED HELP ASAP!!! 100 POINTS

Answer 1

Answer:

A

Step-by-step explanation:

We are given:

$\cos(22f-1)=\sin(7f+4)$

Recall the co-function identity:

$\sin(\theta)=\cos(90-\theta)$

Let θ = 7f + 4. So:

$\sin(7f+4)=\cos(90-(7f+4))$

Substitute:

$\cos(22f-1)=\cos(90-(7f+4))$

Remove the cosine:

$\displaystyle 22f-1=90-(7f+4)$

Distribute:

$22f-1=90-7f-4$

Subtract:

$22f-1=-7f+86$

Add 7f and 1 to both sides:

$29f=87$

Therefore:

$f=3$