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Alexus [3.1K]
2 years ago
9

ASAP Which equation best represents the table below?

Mathematics
1 answer:
Sindrei [870]2 years ago
8 0
I think the answer is D
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WHAT IS THE PRIME FACTORIZATION FOR ONE BILLION
Ivan
1 billion is=1,000,000,000
count the zeros since it has only 10's as the factors
9 zeros
the 10=2 times 5
so there are 10 2's and 10 5's so the prime factorization is
2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 or
2^10 times 5^10
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Find the missing exponent
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The missing exponent is 22
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A bag contains 5 red marbles, 3 white marbles, and 4 blue marbles. what is the probability of randomly selecting a red marble, s
Dennis_Churaev [7]
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3 years ago
What is the length of side BD?
VashaNatasha [74]

Answer:  26.1

<u>Step-by-step explanation:</u>

cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\\cos(40^o)=\dfrac{20}{BD}\\\\\\BD=\dfrac{20}{cos(40^o)}\\\\\\BD=26.1

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Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
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