<h3>The length of longer piece is 30 inches</h3>
<em><u>Solution:</u></em>
Let "x" be the length of longer piece
Let "y" be the length of shorter piece
<em><u>The length of a board is 55 inches</u></em>
Therefore,
x + y = 55 -------- eqn 1
<em><u>The board needs to be cut into 2 pieces with one piece 5 inches longer than the other piece</u></em>
Therefore,
x = 5 + y ------- eqn 2
Substitute eqn 2 in eqn 1
5 + y + y = 55
2y = 55 - 5
2y = 50
<h3>y = 25</h3>
Substitute y = 25 in eqn 1
x + 25 = 55
x = 55 - 25
<h3>x = 30</h3>
Thus the length of longer piece is 30 inches
Step-by-step explanation:
a10 = a + (10-1) (-2)
a10 = a-18
Answer:
The answer is probably c
Step-by-step explanation:
its deducted by the x axis
This is a way to work it out
Add the 18, 16, and 8 together
Then subtract that number from 50.
18+16+8=42
50-42=8
So, 8 patrons don't like either.
