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Ghella [55]
3 years ago
13

A population of 2 rabbits grows at the rate of 400% every two months. How many

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

50 rabbits

Step-by-step explanation:

?/2  =    400/100

multiply 2 by 400

2 times 400 = 800

now, divide it by 100

800/100 = 8

every two months = 8 rabits

12 months in a year

12/ 2 equals 6

6 times 8 = 48

+the two begining rabbits

= 50 total rabbits

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What is the square root of -1​
Romashka [77]

Answer:

i

Step-by-step explanation:

Now, before you think I'm just stealing points, let me explain. The square root of a number is the number that, if you multiply it by itself, it equals that number. The square root of 4 is 2, because 2 * 2 = 4.

Also, a negative number times another negative number, is a positive number. -2 * -2 = 4

With both of those true, then what number could be multiplied by itself to equal a negative number? i.

i is a weird number that I don't really know how to explain all that well. I am sorry, but that is all that I can give you. i is very complex and has various different equivalents, and different meanings, but i is equal to \sqrt{-1}.

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3 years ago
Which of these is a prime number?<br> 733<br> 712<br> 702<br> 725
marishachu [46]

Answer:

733

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In a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per
alexdok [17]

Answer:

The test statistic for testing if the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard is 3.234.

Step-by-step explanation:

We are given that in a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed.

In an independent random sample of 90 cars driven at high altitudes, 24 of them exceeded the standard.

Let p_1 = <u><em>population proportion of cars driven at high altitudes who exceeded a standard of 10 grams</em></u>.

p_2 = <u><em>population proportion of cars driven at low altitudes who exceeded a standard of 10 grams</em></u>.

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the proportion of high-altitude vehicles exceeding the standard is smaller than or equal to the proportion of low-altitude vehicles exceeding the standard}

Alternate Hypothesis, H_A : p_1>p_2      {means that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard}

The test statistics that will be used here is <u>Two-sample z-test statistics</u> for proportions;

                             T.S.  =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~  N(0,1)

where, \hat p_1 = sample proportion of cars driven at high altitudes who exceeded a standard of 10 grams = \frac{24}{90} = 0.27

\hat p_2 = sample proportion of cars driven at low altitudes who exceeded a standard of 10 grams = \frac{42}{380} = 0.11

n_1 = sample of cars driven at high altitudes = 90

n_2 = sample of cars driven at low altitudes = 380

So, the test statistics =  \frac{(0.27-0.11)-(0)}{\sqrt{\frac{0.27(1-0.27)}{90}+\frac{0.11(1-0.11)}{380} } }      

                                   =  3.234

The value of z-test statistics is 3.234.

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