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-Dominant- [34]
3 years ago
10

Add or subtract. Simplify your answer. x+2/x^2−100 + 8/x^2−100

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
\dfrac{x+2}{x^2-100}+\dfrac{8}{x^2-100}=\dfrac{x+2+8}{x^2-100}=\dfrac{x+10}{x^2-10^2}\\\\=\dfrac{x+10}{(x+10)(x-10)}=\dfrac{1}{x-10}\to\fbox{B.}\\\\\\The\ domain:\\D:m\neq0\ and\ m\neq-7\\\\\dfrac{1}{m}=\dfrac{2}{m+7}\ \ \ \ |cross\ multiply\\\\2\cdot m=1\cdot(m+7)\\2m=m+7\ \ \ \ |subtract\ "m"\ from\ both\ sides\\\boxed{m=7}
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Step-by-step explanation:

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3 years ago
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3 years ago
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Question:

The quantities x and y are proportional.

x y

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11.2

Find the constant of proportionality (r) in the equation y=rx

Answer:

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Step-by-step explanation:

Given

The table above

Required

Find the constant of proportionality

The question has an incomplete table but it can still be solved because x and y are proportional.

Given that

y = rx

Make r the subject of formula

Divide through by x

y/x = rx

y/x = r

r = y/x

When y = 7.5, x = 5.8

Substitute these values

r = y/x becomes

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r = (7.5 * 10)/(5.8 * 10)

r = 75/58

In this case, it's best to leave the answer in fraction.

However, it can be solved further.

r = 75/58

r = 1.29 (Approximated)

Hence, the constant of proportionality is 75/58 or 1.29

5 0
3 years ago
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Answer:

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3 years ago
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