Answer=140 fish
200 gallons of water in the first aquarium.
200 gallons of water in the second aquarium.
The first will be for the small fishes.
5 small fish x fish
_____________=__________
10 gallons 200 gallons
cross multiply
10x=1000
divide both sides by 10
x=100 small fish
The first aquarium has 100 small fish.
The second aquarium holds large fish.
8 large fish x fish
____________=___________
40 gallons 200 gallons
cross multiply
40x=1600
divide both sides by 40
x=40 large fish
The second aquarium has 40 large fish.
100small fish+40 large fish=140 total fish
Answer:
5
+5
Step-by-step explanation:
The core uses the value of the Pythagorean theorem and special angles.
Answer:
Step-by-step explanation:
because <u>c</u> is shorter than<u> a</u> we know C is a smaller angle than A
so the first choice is out.
use the law of cosines to find b
= 
=1681+400-1326.787871
= 754.21219
b= 
b= 27.46292
so the last choice looks good
Hello XD
3(x+2) = 3x+6
Distributive property
(3)(x)+(3)(2) = 3x+6
3x+ 6 = 3x+6
Now subtract 3x from both sides
3x+6-3x = 3x+6-3x
6=6
Subtract 6 from both sides
6-6 = 6-6
0=0
In this case the answer is : All real numbers are solution
