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NeX [460]
3 years ago
7

?????????????????????????????????

Mathematics
1 answer:
Sphinxa [80]3 years ago
4 0

c=5/9(f-32)

c=5/9*11

c=6.11111111

c=6.1

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a hovercraft flew 1700 miles in 4 hours. After a 3 hour stop it flew another 600 miles in 3 hours. including the stop what was t
KIM [24]

Answer:

add it

Step-by-step explanation:

3 0
3 years ago
Simplify 27x^7y^2/9x^6y^5
solmaris [256]

Answer: x/y^3

Step-by-step explanation:

So you divide 27/9 which is 3. Then it ix x^7-x^6=x. And then it is y^2-y^5=y3

27*x*x*x*x*x*x*x*y*y/9*x*x*x*x*x*x*y*y*y*y*y

Doing this makes it easier so you cross each variable out for each one in both sides. 3x/y^3 would be your answer.

7 0
3 years ago
If f(x) = 16x-30 and g(x) = 14(x)-6 for which value of x does (f-g) (x) = 0
almond37 [142]
This is a system where (f-g)(x) is wanted.
(16x-30)-(14x-6) .... 2x-24 *be careful with signs and parenthesis placement.

Now set 2x-24 = 0 and so x = 12
6 0
3 years ago
Suppose x=18,y=24, and z=30 in the figure, which is not drawn to scale. Determine the following values. Enter exact answers (as
sammy [17]

Answer:

See explanation

Step-by-step explanation:

cos(θ)= 18/30 = 3/5

sin(θ)= 24/30 = 4/5

tan(θ)= 24/18 = 4/3

cos(ϕ)= 24/30 = 4/5

sin(ϕ)= 18/30 = 3/5

tan(ϕ)= 18/24 = 3/4

3 0
3 years ago
There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

7 0
3 years ago
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