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2 years ago

3(x + 10) + 6 = 3(x + 12)

Mathematics

2 answers:

Talja [164]2 years ago

7 0

Answer:

infinitely many solutions / all solutions

Step-by-step explanation:

you distribute 3x+30+6 = 3x+36
combine like terms 3x+36 = 3x+36
realise the 2 terms are the same so x can be anything

Helga [31]2 years ago

6 0

Answer:

x = infinite amount of solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS
Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

3(x + 10) + 6 = 3(x + 12)

<u>Step 2: Solve for </u><em><u>x</u></em>

Distribute 3: 3x + 30 + 6 = 3x + 36
Combine like terms: 3x + 36 = 3x + 36
Subtract 36 on both sides: 3x = 3x
Divide 3 on both sides: x = x

Here we see that <em>x</em> does indeed equal <em>x</em>. We can plug in any number <em>x</em> and it would render the equation true.

∴ x = infinite amount of solutions

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stepan [7]

Answer:

a) $p_V = 2*P(t_{9} >|2.48|) =0.0349$

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

$0.03 < p_v$

b) $p_V = 2*P(t_{9} >|-3.95|)=0.003355$

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

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We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

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d) $p_V = 2*P(t_{9} >|1.88|) =0.09281$

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

$0.05 < p_v$

Step-by-step explanation:

For this case we are testing the following system of hypothesis:

Null hypothesis: $\mu =0$

Alternative hypothesis: $\mu \neq 0$

The sample size is n=10, so then the degrees of freedom are given by:

$df=n-1= 10-1=9$

In order to calculate the p value we can use the fact that we are conducting a bilateral test so then the p value is given by:

$p_V = 2*P(t_{9} >|t_0|)$

Where $t_0$ represent the calculated or observed statistic.

a) t0= 2.48

$p_V = 2*P(t_{9} >|2.48|) =0.0349$

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

$0.03 < p_v$

b) t0= -3.95

$p_V = 2*P(t_{9} >|-3.95|)=0.003355$

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

$p_v$

c) t0=2.69

$p_V = 2*P(t_{9} >|2.69|) =0.02480$

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

$0.01 < p_v$

d) t0=1.88

$p_V = 2*P(t_{9} >|1.88|) =0.09281$

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

$0.05 < p_v$

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