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uranmaximum [27]
2 years ago
9

The relation R is shown in the table below

Mathematics
2 answers:
spayn [35]2 years ago
6 0
The image doesn’t appear
Ivanshal [37]2 years ago
4 0

Answer:

No image sorry

Step-by-step explanation:

love your username lm.ao

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3. Mr. James told Jill he would charge her $15 per hour, plus parts, to fix her bicycle.
ad-work [718]

Answer:

512

Solution:

so first you multiply 15 times 32 and get 480 than you add 32 and get 512.

7 0
2 years ago
9 = 3(5t -2) help pls
horsena [70]

Answer:

t=1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

4 0
2 years ago
Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)
Elan Coil [88]

Answer:

10u^{3}+4u^{2}-2u+10 or 2(5u^{3}+2u^{2}-u+5)

Step-by-step explanation:

we have

(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)

step 1

Group terms that contain the same variable

(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)

step 2

Combine like terms

(10u^{3})+(4u^{2})+(-2u)+(10)

step 3

Eliminate parenthesis

10u^{3}+4u^{2}-2u+10

step 4

Factor the number 2

2(5u^{3}+2u^{2}-u+5)

8 0
3 years ago
Read 2 more answers
Question regarding logarithms.
Eddi Din [679]

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}

\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}

\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}

6 0
3 years ago
Read 2 more answers
Question 8 of 10
german

Answer:

I believe 8

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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